AFLOW Prototype: ABC_hP6_186_b_b_a-003
Links to this page
https://aflow.org/p/ZZ7U
or
../ABC_hP6_186_b_b_a-003
or
PDF Version
| Prototype | GaGeLi |
| AFLOW prototype label | ABC_hP6_186_b_b_a-003 |
| ICSD | 25310 |
| CCDC | 1601055 |
| Pearson symbol | hP6 |
| Space group number | 186 |
| Space group symbol | $P6_3mc$ |
| AFLOW prototype command |
aflow --proto=ABC_hP6_186_b_b_a-003
--params=$a, \allowbreak c/a, \allowbreak z_{1}, \allowbreak z_{2}, \allowbreak z_{3}$ |
CaAgBi, CaAuBi, CaAuSb, CaHgSn, CaSnZn, CeAgGe, CeAgPb, CeAgSn, CeAuGe, CeAuSn, CeCuSn, DyAgPb, DyAgSn, DyAuGe, DyAuSn, DyCuGe, DyCuPb, DyCuSn, DyPbSb, ErAgSn, ErAuGe, ErCuGe, ErCuPb, ErGaZn, EuAuGe, EuCdPb, EuCdSn, EuHgPb, EuHgSn, GdAgPb, GdAgSn, GdAuGe, GdAuSn, GdCuGe, GdCuPb, GdCuSn, GdPbSb, HfCuSn, HoAgPb, HoAgSn, HoAuGe, HoAuSn, HoCuGe, HoCuPb, LaAgGe, LaAgPb, LaAgSn, LaAuGe, LaAuSn, LaCuSn, LiBiSb, LiBiZn, LiSbZn, LuAgSn, LuAuGe, LuCuPb, LuCuSn, NdAgPb, NdAgSn, NdAsPd, NdAuGe, NdAuSn, NdCuSn, NdPbSb, NdPtSb, PmAuGe, PrAgPb, PrAgSn, PrAuGe, PrAuSn, PrCuSn, PrPdSb, PrPtSb, ScAuGe, ScCuPb, ScCuSn, SmAgPb, SmAsPd, SmAuGe, SmAuSn, SmCuPb, SmCuSn, SrHgPb, SrHgSn, TbAgPb, TbAgSn, TbAuGe, TbAuSn, TbCuGe, TbCuPb, TiCuSn, TmAuGe, TmCuPb, UAuSn, UPdSn, YAgSn, YAuGe, YAuSi, YAuSn, YCuPb, YCuSb, YCuSn, YbAgBi, YbAuBi, YbAuGe, YbAuSb, YbBiCu, YbCuGe, YbHgSn, YbPbZn, YbSnZn
other compoundsso that the (2a) atom is first, but do not guarantee that we are always correct.
Basis vectors
| Lattice coordinates | Cartesian coordinates | Wyckoff position | Atom type | |||
|---|---|---|---|---|---|---|
| $\mathbf{B_{1}}$ | = | $z_{1} \, \mathbf{a}_{3}$ | = | $c z_{1} \,\mathbf{\hat{z}}$ | (2a) | Li I |
| $\mathbf{B_{2}}$ | = | $\left(z_{1} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ | = | $c \left(z_{1} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ | (2a) | Li I |
| $\mathbf{B_{3}}$ | = | $\frac{1}{3} \, \mathbf{a}_{1}+\frac{2}{3} \, \mathbf{a}_{2}+z_{2} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c z_{2} \,\mathbf{\hat{z}}$ | (2b) | Ga I |
| $\mathbf{B_{4}}$ | = | $\frac{2}{3} \, \mathbf{a}_{1}+\frac{1}{3} \, \mathbf{a}_{2}+\left(z_{2} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c \left(z_{2} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ | (2b) | Ga I |
| $\mathbf{B_{5}}$ | = | $\frac{1}{3} \, \mathbf{a}_{1}+\frac{2}{3} \, \mathbf{a}_{2}+z_{3} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c z_{3} \,\mathbf{\hat{z}}$ | (2b) | Ge I |
| $\mathbf{B_{6}}$ | = | $\frac{2}{3} \, \mathbf{a}_{1}+\frac{1}{3} \, \mathbf{a}_{2}+\left(z_{3} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c \left(z_{3} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ | (2b) | Ge I |